Comments on: Algebraic demonstrations that 1=2

By: Ilzar

Ilzar — Fri, 26 Sep 2008 09:05:20 +0000

Two hints :)
1) division per 0 is not allowed (how is say later)
2) When you rewriting as squares you get a modulus values, ie
…
(2-3)^2=(4-3)^2 Factor, rewriting as squares
|2-3|=|4-3|
and only one way to remove modulus this:
1=1
:)

By: arley

arley — Fri, 29 Aug 2008 20:21:52 +0000

Refactored version: 2(0)=1(0) thus 2=1.

By: Luigi

Luigi — Tue, 26 Aug 2008 07:50:36 +0000

Great work guys, you got it. But… Cuius rei demonstrationem mirabilem sane detexi hanc marginis exiguitas non caperet. :)

By: tim

tim — Sun, 24 Aug 2008 20:50:44 +0000

i think u proved 0=0

By: Filippo

Filippo — Sun, 24 Aug 2008 14:06:59 +0000

Nice try!
(Hint: division per 0 is not allowed)